what is the difference between x64 and x86

R

Rebecca

Actually, my posting software is OK, it's configured to post 'exactly the
same as the original post', and in this case the OP was HTML....
No, your reply was to a plain text post. You had to deliberately change to
HTML so you could post using a large font.

<Snip the rest of his lies unread. If he lied about that, who cares what
other lies he has written.>
 
G

Gene E. Bloch

<SNIP everything important :)
Why do you hate it?
If I wish to be dumped into a Google page with 7,930,000 possibly
relevant hits, I prefer to do it myself rather than be surprised by what
looks like an honest link.

Why didn't you ask me why I *did* like the recursive lmgtfy?
 
R

Rebecca

Content-Type: text/html; charset=ISO-8859-15
Content-Transfer-Encoding: quoted-printable

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta content=3D"text/html; charset=3DISO-8859-15"
http-equiv=3D"Content-Type">
</head>
<body bgcolor=3D"#ffffff" text=3D"#000000">
On 3/21/2011 23:34, R. C. White wrote:
<blockquote
cite=3D"mid:[email protected]"
type=3D"cite">Hi, Richard.
<br>
<br>
<blockquote type=3D"cite">Not exactly correct. The first home
computers had what IBM called a 386.
<br>
Then went to a=A0 486.
<br>
</blockquote>
<br>
You're starting a generation or two late.=A0 :^{
<br>
<br>
Depends on your definition of "home computers".
<br>
<br>
My first computer was the original TRS-80, in 1977, with the Z80
chip from Zilog, which was an improvement on Intel's 8080.=A0 IBM's=

first PC (Personal Computer) used the Intel 8088 CPU, which was
16-bit internally but communicated over an 8-bit bus, requiring
each 16-bit word to be divided into two 8-bit bytes, transmitted,
then reassembled at the receiving end. The 8086 (in the AT, for
Advanced Technology) was the first true 16-bit chip used by IBM,
as I recall.=A0 And that was still long before the 32-bit 80386, or=

even the 80286.
<br>
<br>
Most people overlook the 80186, which was a true 16-bit CPU with
16-bit data path.=A0 That's what is in the Tandy 2000, which I
bought in 1983 (and still have in the "museum" in my closet).=A0
This was from Tandy, not IBM, of course, and used TRS-DOS, not
MS-DOS, and was not bothered by the 64-KB limit on usable RAM.=A0 M=
y
machine eventually was upgraded to 768 KB RAM, which was rare in
those days.=A0 The Tandy 2000 was featured in ads in Creative
Computing and other magazines of the day with Bill Gates saying it
would be the perfect machine for his forthcoming new "Windows",
which would be released Real Soon Now.=A0 And, yes, I did run
Windows (1.0) on it - but not long - before Windows 2.0 and, at
last, Windows 3.1, the first really productive version.
<br>
<br>
This is from 30+ year-old memory, so there may be some slight
slippage, but I'm sure it's mostly correct.
<br>
<br>
But Microsoft still should have called it "x32" instead of "x86".
<br>
<br>
RC
<br>
</blockquote>
<font size=3D"+2">Pretty much on the ball park, but the 8086 was not
used on the 'AT' it was used on the 'XT' and in most other clones,
plus several mainframe terminals (smart ones). The advanced clones
used the 80186, a great CPU, but too expensive for the times.<br>
The 'AT' used the 286 and was able to break the 640K barrier since
it implemented 'protect mode', later perfected on the 386 series,
Motorola chips never had such problems since their design was way
ahead of the Intel ones, but were harder to program, at that time
there were not too many 'good, experienced' programmers available,
so Intel took over.<br>
<br>
</font>
</body>
</html>

Still the asshole I see.
 
G

Gene E. Bloch

It was a thorn.
Thanks.

I know the difference - I just don't remember which is which :)

And I was too lazy to look it up. Now that is *truly* lazy.

The penalty? I have to write this reply in a lame attempt to justify
myself :)
 
R

relic

Vic RR Garcia said:
Nyet, assumed the 'x' stand for apples, so we have 86 apples minus 64
apples, we have 22 apples left, so correct result is '22 apples' = x22.
You are so wrong. You failed in math, didn't you. For the answer to retain
'x', the formula would have to be x(86) - x(64) = x(22)
 
G

Gene E. Bloch

Nyet, assumed the 'x' stand for apples, so we have 86 apples minus 64
apples, we have 22 apples left, so correct result is '22 apples' = x22.
Wouldn't it be better in this NG to assume the 'x' stands for PCs?
 
R

ray

You are so wrong. You failed in math, didn't you. For the answer to
retain 'x', the formula would have to be x(86) - x(64) = x(22)
A prefix of 'x' often indicates hexadecimal - note no parens in the OP.
In which case, x86 - x64 = x22 which, in decimal would be 34.
 
Z

Zaphod Beeblebrox

relic said:
You are so wrong. You failed in math, didn't you. For the answer to
retain 'x', the formula would have to be x(86) - x(64) = x(22)
No, x22 is correct - if we rewrote the equation as 86x - 64x = 22x,
you'd agree, correct? Given that accepted notation allows the
elimination of the parenthesis when multiplying a variable by a
constant, and transitive property of multiplication says that x86 =
86x...
 
R

relic

Zaphod Beeblebrox said:
No, x22 is correct - if we rewrote the equation as 86x - 64x = 22x, you'd
agree, correct? Given that accepted notation allows the elimination of
the parenthesis when multiplying a variable by a constant, and transitive
property of multiplication says that x86 = 86x...
<OMG! walks away shaking head>
 
G

Gene E. Bloch

No, x22 is correct - if we rewrote the equation as 86x - 64x = 22x,
you'd agree, correct? Given that accepted notation allows the
elimination of the parenthesis when multiplying a variable by a
constant, and transitive property of multiplication says that x86 =
86x...
Commutative, not transitive.

Transitive is a(bc) = (ab)c.
 
Z

Zaphod Beeblebrox

Gene E. Bloch said:
Commutative, not transitive.

Transitive is a(bc) = (ab)c.
Teach me to rely on my fading memory! I knew the principle, just not
the correct term. Sigh.

--
Zaphod

Arthur Dent, speaking to Trillian about Zaphod:
"So, two heads is what does it for a girl?"
"...Anything else he's got two of?"
 
G

Gene E. Bloch

I'm pretty sure that's more than I expected to learn!
Not that I can be pedantic or anything... :)
As if I had the power to warn anyone. ;-)
It worked on me. You should try it on others - you never know what
superpowers you might discover.

But then you'd have to budget for a superhero costume.

Which made me wonder how you might look in tights, and so I inevitably
recalled that yesterday the DMV took a picture of me for my license
renewal. OMG, I'm ugly! Tights just won't help...

And by now I'm beginning to think that my superpower might be OT posting
:)
 
K

Ken Blake

Thanks.

I know the difference - I just don't remember which is which :)

And I was too lazy to look it up. Now that is *truly* lazy.

The penalty? I have to write this reply in a lame attempt to justify
myself :)

LOL! I was pretty sure it was a thorn, but looked it up to be on the
safe side.

The way I always remember what a thorn looks like is "Ye Olde
Something-or-Other Shoppe." Almost everyone pronounces the first word
of it as YEE, but of course, it's really a thorn, not a Y, but printed
or written with a Y because it's the modern letter that looks most
like a thorn. So it's the same word as our modern "the," and
pronounced the same way, even though it looks very different.
 
J

Jack

Zaphod Beeblebrox said:
No, x22 is correct - if we rewrote the equation as 86x - 64x = 22x, you'd
agree, correct? Given that accepted notation allows the elimination of
the parenthesis when multiplying a variable by a constant, and transitive
property of multiplication says that x86 = 86x...
How about just keeping it simple.
6 - 4 = 2
8 - 6 = 2
x - x = 0
 
B

Bob I

Hi, Bob.


Still not exactly correct. The 8088 was 16-bit internally, but
communicated through an 8-bit bus, so each transmission had to be
divided into two 8-bit segments, which were transmitted sequentially and
then reassembled at the other end. Or so I'm told; I'm not a techie.

The 8086 was Intel's first full 16-bit CPU with a 16-bit bus.
Yes the reason that IBM used the 8088 was that the 8 bit data bus and
memory made the motherboard considerably cheaper than 16 bit parts, but
the CPU was indeed a 16 bit unit, and IBM didn't use the 8086. (but IBM
PC clones did)
 
G

Gene E. Bloch

LOL! I was pretty sure it was a thorn, but looked it up to be on the
safe side.

The way I always remember what a thorn looks like is "Ye Olde
Something-or-Other Shoppe." Almost everyone pronounces the first word
of it as YEE, but of course, it's really a thorn, not a Y, but printed
or written with a Y because it's the modern letter that looks most
like a thorn. So it's the same word as our modern "the," and
pronounced the same way, even though it looks very different.
You've helped me solve a thorny memory problem - thanks - but only if I
can remember than it's the thorn, not the eth, in Ye Olde Gifte Shoppe.

OK, I've got it: Ye Olde Cactus Shoppe.
 
G

Gene E. Bloch

Teach me to rely on my fading memory! I knew the principle, just not
the correct term. Sigh.
Think of it this way: I took advantage of the only thing I can remember
:)
 

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